Fluid Dynamics?

Question

A cylindrical container with a cross-sectional area of 65.2cm^2 holds a fluid of density 806 kg/m^3. At the bottom of the container the pressure is 116 kPa.

What is the depth of the fluid?

What equation do i have to use to figure depth out

Answer 1

Pressure = force/area = rho*g*h*area/area = rho*g*h

where rho is the desnity of the fluid.