What is the container's volume?
What is the pressure if the temperature is raised to 150 degrees Celsius?
2007-09-18 14:17:37 · 2 answers · asked by ryoukai_chang 1 in Science & Mathematics ➔ Physics
This problem can be easily solved with ideal gas law:
PV = nRT, where R = 0.082057 L·atm/(mol·K) if P is in atm, V in L, n in mol and T in K. Remember that 40 degrees C = 313.15K. Please go ahead to solve it yourself.
2007-09-21 17:49:07 · answer #1 · answered by Hahaha 7 · 0⤊ 0⤋
because of the fact the quantity does no longer substitute (cylinder with fixed quantity) based on the equation PV=nRT the place V, T and R are consistent for the two gadgets of situations, Use the equation P1/n1T1 = P2/n2T2 and remedy for n2 to get the moles interior the 2d difficulty. bypass multiplying you get P1n2=P2n1 and dividing the two factors by P1 you get n2 = n1 (P2) / (P1) P1=one hundred fifty atm; P2=13 atm n2=one hundred fifty/13=11.5 mol. Argon has an molar mass of 39.948, so grams = 11.5 x 39.948 = 461 g
2016-10-19 01:21:58 · answer #2 · answered by ? 4 · 0⤊ 0⤋