A car starts from rest and accelerates for 8.6 seconds....?

Question

A car starts from rest and accelerates for 8.6 seconds with an acceleration of 2.8 m/s^2
How far does it travel in meters?

Answer 1

Use s = ut + 1/2 a t^2, where s is the distance travelled, u the initial velocity, zero in this case since it starts from rest, a the acceleration, and t the time, so

s = ut + 1/2 at^2

s = 0 + 1/2 x 2.8 x 8.6 x 8.6

s = 103.5 m.

Hope this helps, Twiggy.

Answer 2

d = V(initial) * t + 1/2 a * t^2

V(initial) = 0 m/s (car is at rest)
t = 8.6 s (given)
a = 2.8 m/s^2 (given)

d = 1.4 * (8.6)^2 = 103.5 m

Keeping in mind only 2 sig figs from the numbers in the problem, I hate to report my final answer as 1.0 x 10^2 m.

Answer 3

1/2 acceration * time^2 = distance

1/2 (2.8 * (8.6)^2) = 103.544 m

Answer 4

do 8.6 times 2.8 and label it meters.24.08m.?