Physics of a sharp turn?

Question

Okay there is a sharp turn going down the road toward my house. Everytime I turn on it I must slow down. Can someone please tell me the physics of this. Does this have to do with Angular momentum? Friction? I have no clue and I decided to do a project on it just because I have nothing else. Thanks for the answers. God bless!

Answer 1

When you turn you add a centripetal force to the tires that friction must resist.

Assume your car tire has friction coefficient of 0.8, which is typical for tire-asphalt interface.

If the car weighs 2000 kg ( a small car), the maximum force the car can experience without skidding is
2000*g*0.8 N
using g=10
16000 n is the max.

The centripetal force is related to the translational speed and turn radius is:
m*v^2/r

this force increases exponentially with respect to speed and decreases linearly with respect to the radius of the turn.

The minimum turn radius required in Santa Clara County is 42 ft, or about 14 meters. 60 ft, or a minimum of 20 meters is required for access by hook and ladder trucks, a bit of trivia.

What is the maximum speed you can corner on a 14 meter road?

recall
m*g*u>m*v^2/*r
note that m divides out.
solve for v
v
For a 14 meter radius turn
v v<10.58 m/s
or<23.7 mile per hour

for a 60 ft radius, or 20 meters
v<28.3 mph

When the road is banked, the maximum speed increases because the normal force of the car is increased by the banking. That's why we feel a bit heavier in our seats when cornering on a banked road.

j

Answer 2

Any object that's in motion will tend to travel in a straight line until a force is applied to change it's direction. The front tires on your car do this by producing friction against the road surface. If your speed is high enough to overcome this friction then your tires slip on the road and you have a skid.

Answer 3

One of Newton`s laws of motion ( can`t remember which one) states that a body continues in a state of rest or uniform motion unless acted upon by some external force. When you turn the steering wheel to change your direction of motion, that exerts an external force on your car, which results in a frictional force between the tyre and the road, causing you to slow down.

Answer 4

its friction and inertia..

when you are going fast.. and you go to turn real sharp..

The inertia of your vehicle is going to try to carry it forward(the direction of travel)..

your tires can only hold to the pavement with friction..
different tires can hold better obviously..
the force and speed are too much for the friction of the tires to hold it on the road..


then you go into some crazy momentum phics and how a car rolls

Answer 5

Hi, it has to do with accleration. This is when an object in motion speeds up, slows down. Friction would be more if you came to a screeching hault.

Acceleration occurs when the speed of an object changes or its direction of motion changes.

You calculate acceleration in this formula:

Final velocity(m/s) - initial velocity(m/s)
----------------------------------------------------
Final time (s) - initial time (s)

Since you say your speed is decreasing then the answer form this equation would be negative.

Good luck and always study science!

Answer 6

well i'm no physics major or nothing but i do build roads. now you may not realize it but in curves most roads have a ...................................never mind i don't feel like getting into it and you don't really care.