2007-09-18 12:55:55 · 5 answers · asked by yeah! yeah! yeah! 1964 1 in Science & Mathematics ➔ Physics
The velocity of gravity is -9.81 m/s. So the first second of falling it fell 9.81 meters. Then the rest of the trip down was .4 of a second. 9.81 multiplied by .4 equals 3.924. 9.81 plus 3.924 equals 13.734. So the apple fell 13.734 meters.
2007-09-18 14:47:05 · answer #1 · answered by Mike H 1 · 1⤊ 0⤋
Time taken via coconut to fall = one million.5 sec Acceleration via gravity = 10 m/s^2 initially the coconut became at relax So preliminary velocity = 0m/s (u) via the formula S= ut + one million/2 at^2 the place s is distance or as a result top of tree S= 0 * one million.5 + one million/2 * 10 (one million.5)^2 s= 0 + 5 * 2.25 s= 11.25 m i ought to in common terms discern it out till finally here via fact there became inadequate records. and see despite if the coconut is two m from trunk or 5 m from trunk that's going to fall with the comparable velocity in comparable volume of time so there is no way confirm how far that's going to fall.
2016-12-17 04:43:21 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Distance Formula
d = 1/2 gt^2
d = 1/2 *9.81 * (1.4)^2
d= 0.5 * 9.81* 1.4*1.4 = 9.6138 m
d = 9.6138 m
or if g is aproximate to = 10 m/s^2
d = 0.5*10*1.4*1.4 = 9.8 m
2007-09-18 13:09:40 · answer #3 · answered by collinss_69 2 · 0⤊ 0⤋
use
y(t)=-.5*g*t^2
distance is y
t is 1.4
g=10 m/s
y=5*1.4^2
y=9.8 m
or
g=32 ft/sec^2
y=31.4 ft
j
2007-09-18 12:59:02 · answer #4 · answered by odu83 7 · 0⤊ 0⤋
13.72 meters
2007-09-18 13:01:05 · answer #5 · answered by bisalabisa2000 2 · 0⤊ 0⤋