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Super easy!

A jet carries 342 passengers with 36 in first-class and the rest in coach. Suppose a first class ticket to fly from Los Angeles to Chicago costs $750 and a coach ticket costs $450. Use the four step problem solving plan to find the greatest possible ticket sales on one flight.

I'm an idiot, could you show me the steps and the solution?

2007-09-18 12:53:15 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

You have 342 passenger, with 36 in first-class. So you have 342-36 passengers in coach.

Total sales for a full first-class section are 36 x $750.00.

Total sales for a full coach section are 306 x $450.00.

Total sales for a full plane are the sum of the 2 results above.

2007-09-18 13:04:20 · answer #1 · answered by daa 7 · 1 0

First, i subtract 36 (# in first-class) from 342 (total passengers) that equal 306 (# in coach).Then i multiply 36 (# in first-class) times $750 equal $27000. then multiply 306 (# in coach) time $450 equal $137700.Then added the two product to get the total possible ticket sales on this one flight is $164,700.

2007-09-18 13:20:05 · answer #2 · answered by donnyak49 1 · 1 0

14 + 12 + 5 = 31 so 2 students are wearing both a) 14+12-2 = 24 b) 14-2 = 12 c) 12-2 = 10 Please note that alot of people will answer 26 for the first question, however this is incorrect: 29 - 5 = 24 (minus of people who arent wearing red OR blue 14+12 = 26 there is 26 blue and red colours but only 24 students this means 2 people must be wearing both colours as I just mentioned there is only 24 people so how many red and blue = 24 red not blue = red people less the people who wearing both blue not red = blue people less the people who wearing both

2016-05-18 00:14:17 · answer #3 · answered by ? 3 · 0 0

oh my ...... erm i answered but no good at math

2007-09-21 09:48:24 · answer #4 · answered by Anonymous · 1 0

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