English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

A race car can be slowed with a constant acceleration of -11 m/s

A) If the car is going 55 m/s how many meters will it take to stop?

B) How many meters will it take to stop a car going twice as fast?


I don't understand how you can do this problem when they only give you one piece of information.

I'm not trying to get someone to do my homework for me, I just really don't know where to begin, I've never been good in applying math to science.

2007-09-18 12:24:19 · 1 answers · asked by Katie E 2 in Science & Mathematics Physics

1 answers

you use the suvat equation

v^2=u^2+2as

although you arnt given it you know the v because when a car is at rest its velocity is 0 so suvat becomes:

s=? - you want to find this
u=55
v=0
a=-11
t=? - you dont need

plugging values in you can get an answer then you should be able to work out part b

2007-09-18 12:47:11 · answer #1 · answered by , 2 · 0 0

fedest.com, questions and answers