plz help in math?

Question

1/a +1/q = 1/g

solve for q
thanx all answers

Answer 1

1/q = 1/g - 1/a

1/q = (a - g )/ ag

q = ag / (a - g)

Answer 2

solve for q means you have to make q as subject

bring q term to left side and others to right side
1/q = 1/g - 1/a
make denominator equal on right side by multiplying 1/g with a/a and 1/a with g/g
1/q = a/ag - g/ag
= a- g/ag
take reciprocals

q = ag/(a - g)

Answer 3

The answer will have to be in terms of a and g, unless you have values for the two other variables around

gq / agq + ag / agq = aq / agq (getting the common denominator)

gq + ag = aq (multiplied equation by agq)

gq - aq = - ag (moving q terms to same side, moved ag term to other side)

q (g-a) = -ag (factoring)

q = -ag / (g-a) (division)

Answer 4

okay.
well you get that you subtract first- you're trying to get q by itself.

so 1/g minus 1/a.

then you have 1/q = 1/g - 1/a.

to subtract fractions, the denominator must be the same.

so 1/q = a-g/ga

take the reciprocal of both sides.

you get q= ga/(a-g)

i hope this helps!

Answer 5

right...
always remember to always find the GCF whenever you add fractions with different denominators..
here, the GCF of course will be (aqg)
multiplying:
(1/a +1/q = 1/g)aqg
multiplying;
qg + ag = aq
then combine same terms,
aq - qg = ag
factor out q:
q(a-g) = ag
then divide:
q = ag/(a-g)=answer

hope this helps!

Answer 6

1/a + 1/q = 1/g, subtract 1/a
1/q = 1/g - 1/a, multiply both sides by q
1 = q(1/g - 1/a), divide by 1/g - 1/a
1/(1/g - 1/a) = q