A youngster bounces straight up and down on a trampoline. Suppose she quintuples her initial speed from 1.9 m/s to 9.5 m/s.
(a) By what factor does her time in the air increase?
-What is the intial speed (in seconds)?
-What is the speed (in seconds) after it quintuples?
(b) By what factor does her maximum height increase?
-What is the intial height (m)?
-What is the height (m) after the intial speed quintuples?
Thanks for the help i've been stuck on these questions for an hour now. How do you do these???? THANKS! :)
2007-09-18 10:45:21 · 3 answers · asked by Natlsn12009 1 in Science & Mathematics ➔ Physics
a)At max height v=0 and v=vo-at
so time to max height 0=vo-at so t=vo/a
factor time in the air increase =5
b) use energy conservation 1/2mvo^2=mgh
h=vo^2/2g
factor = square root of 5
2007-09-18 11:16:56 · answer #1 · answered by meg 7 · 0⤊ 0⤋
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2016-10-09 10:23:07 · answer #2 · answered by ? 4 · 0⤊ 0⤋
I won't do your homework for you. The biggest hint I can give you is
Displacement=V(naught)t*.5*-9.8*t^2
its simple, try that and if nothing, ahh, you'll get it.
Height in seconds?
2007-09-18 11:07:28 · answer #3 · answered by Wastedmilkman61 3 · 0⤊ 0⤋