Having a problem with this math problem
Y= 1 / x-3 ^2
2007-09-18 10:28:14 · 5 answers · asked by joemelle k 2 in Science & Mathematics ➔ Mathematics
so you must be doing functions? if you want to make a function table, then you are going to use -1, -2, 0, 1, and 2 substituting for x. then lay it out in table and form and graph it if necessary.
2007-09-18 10:36:05 · answer #1 · answered by Rock*Star 3 · 0⤊ 0⤋
y^2 = 1 / (x^2 - 6x + 9)
You just square the top and the bottom, but of course 1^2 is just 1
2007-09-18 17:35:09 · answer #2 · answered by quailman67 2 · 0⤊ 0⤋
The x-axis is a horizontal asymptote
The line x= 3 is a vertical asymptote
y is always positive. Its range is (0, +infinity) or 0
There are no real roots. There are two imaginary roots.
2007-09-18 17:40:21 · answer #3 · answered by ironduke8159 7 · 0⤊ 1⤋
something wrong!, with the problem , it is not written right, otherwise how come nobody solved it!, Find Y. is what
he wants!, find it!
2007-09-18 17:33:27 · answer #4 · answered by Dragon'sFire 6 · 0⤊ 0⤋
sqrt(y) = sqrt(1/(x-3)^2
sqrt(y) = 1/(x-3)
2007-09-18 17:35:11 · answer #5 · answered by frank 7 · 0⤊ 0⤋