solve for x
2^x = 3 / 5
2007-09-18 10:21:48 · 4 answers · asked by Arianna A 1 in Science & Mathematics ➔ Mathematics
x =log_2(3/5)
2007-09-18 10:28:11 · answer #1 · answered by pegminer 7 · 0⤊ 0⤋
umm i don't remember, but i know it has to do with natural logs. so maybe the natural log of x squared is equal to the natural log of 5/3... but it's been awhile...
2007-09-18 10:29:56 · answer #2 · answered by jessi f 2 · 0⤊ 0⤋
The trick is to use logarithms. I've attached a website that explains it in detail.
2007-09-18 10:41:05 · answer #3 · answered by Ken 1 · 0⤊ 0⤋
You need to use logs...
log(2^x)=log(3/5)
xlog(2)= log(3) - log(5) because log(a^b)= (b)log(a) , and log(a/b)=log(a) - log(b)
x = [log(3) - log(5)]/log(2) multiplying both sides by 1/log(2)
The arithmetic is up to you... or you can let somebody do it for you...
2007-09-18 10:36:09 · answer #4 · answered by gugliamo00 7 · 0⤊ 0⤋