Find the line containing the points?

Question

Find the line containing the points (-6, -1) and (2 , -13)

Answer 1

m = (- 13 + 1) / (2 + 6) = - 12 / 8 = - 3 / 2
y + 13 = (-3/2) (x - 2)
y = (- 3/2) x + 3 - 13
y = (- 3/2) x - 10

Answer 2

To get the equation of a line you need two things:
The slope, and a point on that line.

As you have two points, you can find the slope by using (y2 - y2)/(x2 - x1)
So... -12/8 = -4/3 = the slope.

Now use the formula for the equation of a line (y - y1) = m(x - x1) where m is the slope... I'll take the first point, but you can use either of them.

y -(-1) = -4/3(x - (-6))
3y + 3 = -4x -24
4x + 3y + 27 = 0