Help please..urgent question.?

Question

The product of 2 consecutive odd numbers is 10 more than the square of the smaller number. Find the smaller number.
Can somone give me the formula for this? THANKS!

Answer 1

the smaller number is 5.

(x)(x+2)=x^2+10

x^2+2x=x^2+10

2x+10,

x=5

Answer 2

If one number is x, the 'next' odd number is x+2 (i.e., if x is 7, x+2 would be 9 to get to the next odd)...

x(x+2) = 10 + x^2
x^2 + 2x = x^2 + 10
2x = 10
x = 5
(x+2 = 7, which is your second number)

Answer 3

let x be the first odd number
x + 2 is the second odd number

pruduct means multilication

x(x + 2) = 10 + x^2

x^2 + 2x = 10 + x^2

2x = 10

x = 5

the smaller number is 5

Answer 4

(2x + 1)(2x+ 3) = 10 + (2x+1)^2. So
4x^2 + 8x + 3 = 10 + 4x^2 + 4x+ 1, and
4x = 8, and x = 2, so the numbers are 5, 7.

Test it: 35 = 10 + 5^2 -- ok

Answer 5

Let n be the smaller odd number. Then n+2 is the larger and

n*(n+2) = n^2+10

n^2 +2n = n^2 +10

2n = 10

n=5

n+2 =7

Answer 6

x*(x+2) = x^2+10 where x is the smaller and x+2 is the larger number

hope you can solve this

Answer 7

let nos are x & x+2
so x(x+2)=x^2+10
or x^2+2x=x^2+10
or x=5 & x+2=7