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Question

Ok...I just need someone to explain to me how to do these because I am not getting it for some reason...I have 10 to do and if someone could help me with one I would really appreciate it...I just am lost when it comes to trying to figure all this stuff out with limited information given...

A bus leaves a station at 1pm, traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what time will the two buses be 274 miles apart?

Answer 1

This is the way I think of it. Once the second bus leaves they are already 44 miles apart, since the first one left an hour ago going 44mph. So, you need to find out how long it takes them to get an additional 230 miles away from eachother.
x=hours
44x(speed of 1st bus) + 48x(speed of second bus) = 230
92x=230
x= 2.5. So 2.5 hours from the time the second bus leaves. It left at 2:00, so the answer is 4:30.

Answer 2

The first bus that is traveling west is 44 miles away from the second bus when it leaves the station. So, you really need to know how long it will take after the second bus leaves before the two buses travel 230 miles (274 - 44). For these problems I just use trial and error until I arrive at the answer. Start somewhere logical. Let's start with how far they will be two hours after the second bus leaves: 2 X 44 = 88 plus 2 X 48 = 96...88 + 96 = 184. Remember we are looking for how long for 230...so now we know it is more than 2 hours. So, now try 3 hours: 3 X 44 = 132 plus 3 X 48 = 144... 132 + 144 = 276. Again, we are looking for 230...so now we know it is between 2 and 3 hours. So, now try 2.5: 2.5 X 44 = 110 plus 2.5 X 48 = 120...110 + 120 = 230...boom we found it. So, they will be 274 miles apart 2.5 hours after the second bus leaves the station. There is also a way to do this algebraically...but I prefer to use trial and error. Once you get used to it...then it doesn't take that long.

Answer = 2.5 hours after the second bus leaves the station or 3.5 hours after the first bus leaves the station.

Answer 3

OK here we go.
Let's take it 1 hour at a time
After 1 hour the first bus (Let's call it A) is 44 miles west
After 2 hours Bus A is 88 miles west and the other (B) is 48 miles east. So far then they are 132 miles apart (44 + 88)
After 3 hours A is132 miles west and B is 92 miles east so they're 132 + 92 miles apart = 224. Now the average speed of moving apart is (44 + 48)/2 = 92/2 = 46 mph.
To be 274 miles apart they need to travel another 50 miles and as there are two of them we divide the 46 in two = 23 so in another 23/50 hours the distance will be achieved.
There are 60 minutes in an hour
so (23 x 60)/50 = 1380/50 = 27 3/5 minutes plus the three hours is your answer 3 hours 27 minutes and 36 seconds.

Answer 4

They are 44 miles apart when second bus leaves station at 2pm,

274 miles - 44 miles = 234 miles

The 2 buses depart from each other at the rate of 92 m/h (44m/h + 48m/h = 92m/h)

234 miles / 92m/h =2.5 hours later they are 274 miles apart
the answer is "at 4:30pm"

Answer 5

Typically, you do just 10*nine*eight*7*6*five*four*three*two*one million. Because you begin with one million man or woman, he shakes every body's hand, then the following man or woman is going, he has all able shook that first individuals hand, so that is one much less individuals hand he has to shake, etc. So the reply is 3628800 handshakes.