angles, where will the jumper land?

Question

A world class long jumper leaves the ground with a velocity 7 m/s at an angle 35 degrees above the horizontal.

How far is the jump?

I get 5.8 m ...is that right?

Answer 1

The length of the jump is
x(t)=7*cos(35)*t
find the flight time, t

Since we know the vertical velocity, half the flight time will be when vy(t)=0, or
0=7*sin(35)-g*t
t=7*sin(35)/g
twice this is
14*sin(35)/g

plug this into x(t)
x(t)=7*cos(35)*14*sin(35)/g
using g=10

I get 4.6 m

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