An elevator accelerates upward at 1.2 m/s/s. The acceleration of gravity is 9.8 m/s/s. What is the upward force exerted by the floor of the elevator on a 77 kg passenger? Answer in units of N.
If the same elevator accelerates downwards with an acceleration of 1.2 m/s/s, what is the upward force exerted by the elevator floor on the passenger? Answer in units of N,
2007-09-18 09:25:10 · 2 answers · asked by josh j 1 in Science & Mathematics ➔ Physics
You add the upward acceleration to the gravitation acceleration and subtract the downward. Then use the total in F=ma to get the force F=ma.
2007-09-18 11:58:07 · answer #1 · answered by meg 7 · 0⤊ 0⤋
Howdy ! the lever duration is in inverse ratio to the load sooo should you push down 10 kilos by way of 10 ft you'll carry one hundred kilos in a million foot...the ratios are the important thing to the lever load forces..the MA for yours is 10:a million..there ya cross from the E..
2016-09-05 18:32:49 · answer #2 · answered by harlie 4 · 0⤊ 0⤋