Physics help???????????

Question

A dolly and its wheels have negligible mass.
The object on the dolly weighs 304 N and
the force on the rope is 23 N. The
acceleration of gravity is 9.8 m/s/s.

If a person pulls on the rope with a
constant force what is the
acceleration of the system? Answer in
units of m/s/s.

How far will it move in 3.29 s?
Answer in units of m.

Assume the system starts from rest and there are no frictional forces opposing the motion of the system.

Answer 1

Use F=m*a
the mass is 304/g N
or 304/9.8

so
23=a*304/9.8
solve for a

once you have a, plug into the following equation for displacement
s(t)=.5*a*t^2
along with t=3.29.

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