please help me find equation instandard form with all interger coefficients of the line perpendicular to x+3y=12 and passing through (9,-5)
2007-09-18 06:30:39 · 3 answers · asked by Onika D 1 in Science & Mathematics ➔ Mathematics
The slope of the given line is (- 1/3); therefore the slope of a line perpendicular to the line would be 3. Substitute into the point slope form and get y+5 = 3(x -9) since there is no fractions remove ( ) and then put into the form you want it. Probably Ax + By = C.
2007-09-18 06:39:31 · answer #1 · answered by Jo G 1 · 0⤊ 0⤋
The slope of the given line is -1/3 so slope of line perpendicular to it will be -(1/-1/3) = 3
So y = 3x + b
Since the above line passes theough (9,-5) we have:
-5 =3(9) + b --> b= -32
So equation is y = 3x -32
Instadard form we have 3x - y -32 = 0
2007-09-18 13:43:33 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
x+3y=12 and passing through (9,-5)
3y = -x + 12
y = - 1/3 x + 4
slope of this line is - 1/3
slope of a perpendiculare line is +3/1 = 3
y = mx + b
-5 = 3(9) + b
b = -32
y = 3x - 32 ---> slope intercept form
3x - y = 32 ---> standard form
2007-09-18 13:41:14 · answer #3 · answered by Marvin 4 · 0⤊ 0⤋