A 0.4230 g sample of impure sodium nitrate (contains sodium nitrate plus inert ingredients) was heated, converting all the sodium nitrate to 0.2292 g of sodium nitrite and oxygen gas. Determine the percent of sodium nitrate in the original sample.
sodium nitrate in the original sample =__________%
I'm having I very tough time with this problem, can someone pleeze help me! I hate Chemistry, it's so hard :(
2007-09-18 06:30:15 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
2NaNO3 ===> 2NaNO2 + O2
Atomic weights: Na=23 N=14 O=16 NaNO3=85 NaNO2=69
0.2292gNaNO2 x 1molNaNO2/69gNaNO2 x 2molNaNO3/2molNaNO2 x 85gNaNO3/1molNaNO3 = 0.2823g NaNO3 in the original sample.
Let thge sample be called S.
0.2823gNaNO3/0.4230gS x 100% = 66.75% NaNO3 in the original sample.
2007-09-18 06:49:51 · answer #1 · answered by steve_geo1 7 · 1⤊ 1⤋
3%
2007-09-18 06:49:12 · answer #2 · answered by jerryguy 3 · 0⤊ 1⤋