Hypothetical element X has 3 stable isotopes. The relative peak intensities are 57.66 for 180.0 u, 100.0 for 184.0 u, and 84.10 for 186.0 u. What is the average atomic mass for X?
2007-09-18 05:35:03 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
[(57.66 * 180.0) + (100.0 * 184.0) + (84.10 * 186.0)]/(57.66 + 100.0 + 84.10) =
[10378.8 + 18400 + 15642.6]/241.76 = 183.74 amu
2007-09-18 05:49:11 · answer #1 · answered by Dave_Stark 7 · 0⤊ 0⤋
first to make sparkling is atomic mass unit = no of proton and neutron. it does not incorporate electron by using fact the mass of an electron is a million/1834 a.m.u. and this variety is negligible. by using fact that is an atom, electric powered charge is 0.
2016-12-26 16:46:42 · answer #2 · answered by ? 4 · 0⤊ 0⤋
a
2007-09-18 05:41:37 · answer #3 · answered by Anonymous · 0⤊ 0⤋