which do you prefer
I'd much rather R&J
2007-09-18 05:29:17 · 18 answers · asked by Anonymous in Entertainment & Music ➔ Polls & Surveys
Please, please...has to be Richard and Judy!
2007-09-18 19:01:04 · answer #1 · answered by TheatreFan 6 · 0⤊ 0⤋
Richard and Judy, that Paul o'Grady winds me up so much! He's so loud and crude and nasty, at least with Richard and Judy you can enjoy a nice nap while it's on!
2007-09-18 05:58:37 · answer #2 · answered by floppity 7 · 0⤊ 0⤋
Here I am in the USA. Wondering who Richard & Judy Paul O'Grady are? I'm American Irish so I chose Paul O'Grady just for his name sake. My favorite is Absolutely Fabulous. I know it isn't on anymore but I have every single episode!!! AB FAB for life!!! I love Edie (I think they may have partially carved her character from portions of my life), Pats and Saffron (sweetie). Also Hyacinth and Richard Bucket (pronounced Bouquet by Hyacinth).
2007-09-18 13:50:17 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Paul o'grady was much better as Lilly Savage.
And Judy Finnigan has better cleavage.
2007-09-18 05:39:20 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I met Paul O'grady once so I would go for him but I like all of them.
2007-09-18 05:34:24 · answer #5 · answered by Ginny Jin 7 · 0⤊ 0⤋
Definitely Paul O'Grady, he's from my home town and has a great sense of humour.
2007-09-18 05:39:00 · answer #6 · answered by pinkkittenliverpool 6 · 0⤊ 0⤋
Paul O'Grady...
2007-09-18 05:34:39 · answer #7 · answered by Polo 7 · 0⤊ 0⤋
Hmm tough choice.
Guess it would have to be Paul O'Grady but I'm not too keen on his guests.
2007-09-18 05:50:33 · answer #8 · answered by Just Me 6 · 0⤊ 0⤋
If I can't say "none of the above", I'll have to go with Richard & Judy.
2007-09-18 05:36:19 · answer #9 · answered by hello world 7 · 0⤊ 0⤋
paul o'grady
2007-09-18 05:33:54 · answer #10 · answered by richard_beckham2001 7 · 0⤊ 0⤋
Richard&Judith! paul o'gravey gets on my t**s lol xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
2007-09-18 23:30:38 · answer #11 · answered by Bluebudgie21 5 · 0⤊ 0⤋