How do you find the Average Rate of Change (ARC) of an equation, let's say:
Given f1(x)=-3x^2+12x+3, on x-range:[-1...5] and y-range: [-10...18]...
What is the ARC? Please help I have a test over this Friday!
2007-09-18 05:11:59 · 2 answers · asked by Jet 2 in Science & Mathematics ➔ Mathematics
ARC = [f(b)-f(a)]/(b-a)
In your case, b=5 and a = -1
So ARC = [f(5)-f(-1)]/(5-(-1)) = [f(5)-f(-1)]/6
f(5) = -375 +60 +3 = -312
f(-1) = 3-12+3 = -12
So ARC = (-312-(-12))/6 =-300/6 = -50
Your y-range values in your example do not correlate with you x values.
2007-09-18 05:31:56 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
The average rate of change depends on a given interval. For example, the average rate of change over the interval [-1,0], for your given function, is as follows:
(f(0)-f(-1))/(0-(-1))=(3-(-6))/(1)=9
This number can also be interpreted as the slope of the secant line which intersects (-1,-6) and (0,3).
2007-09-18 05:38:57 · answer #2 · answered by Anonymous · 0⤊ 0⤋