okay i dont know how to do the fraction ones so please help! i am being homebound so this is why im struggling. please explain your answer so i can understand thanks!
'' use elimination to solve each system of equations''
2/3x - 3y = 1/5
2x - 9y = 4
2007-09-18 03:58:42 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2/3x - 3y = 1/5- - - - -Equation 1
2x - 9y = 4- - - - - - - -Equation 2
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Multiply equation 1 by 15
15(2/3x) - 15(3y) = 15(1/5)
10x - 45x = 3. . .new equation 1
Conbine the new equation 1 with equation 2
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10x - 45y = 3
2x - 9y = 4
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Multiply equation 2 by - 5
- 5(2x) - (- 5)(9y) = - 5(4)
- 10x - ( - 45y = - 20
- 10x + 45y = - 20. . New equation 2
conbine new equation 1 with new equation 2
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10x - 45y = 3
- 10x + 45y = - 20
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The coefficients and variables cancell. No solution
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2007-09-18 04:51:57 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
Multiply the fraction one through by 15.
10x - 45y = 3
2x - 9y = 4
Multiply the second guy by -5 and add the two. This will cancel the 'x' term.
Whoa! It cancels the 'y' term as well. This tells me these two lines are parallel and have no intersection.
2007-09-18 11:05:43 · answer #2 · answered by PMP 5 · 1⤊ 0⤋
i dont think u can do it
I get 4/3 = 1/5
which of course, isn't true
2007-09-18 11:06:29 · answer #3 · answered by andy s 2 · 0⤊ 0⤋