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Evaluate the indefinite integral (dx/8x^4)?

2007-09-18 03:27:36 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

1 answers

integral (dx/8x^4) = 1/8 integral (dx/x^4) = 1/8 integral (x^(-4) dx = 1/8 x(-4 +1)/(-4 +1) + C = -1/(24x^3) + C

2007-09-18 04:01:09 · answer #1 · answered by Steiner 7 · 0⤊ 0⤋

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