Solve this simple integration?

Question

integrate x/(x+1) dx

Please show the steps clearly

Answer 1

divide x/x+1
x/x+1=1-1/(x+1)
integral(1-1/(x+1) dx)
x-In(x+1)+C
you may further simplify this
Ine^x-In(x+1)+Ine^C
In[(e^x*e^C)/(x+1)]
In[(e^(x+C)/(x+1)]

Answer 2

Integral x/x+1 dx = Int.{(x+1) - 1}/x+1 =
Int. 1dx - 1/x+1dx = x - log (x+1) + C.

Answer is: x - log(x+1) + C.