Find x:
2x = 3y - 6
x = 1/2y - 3
Find y:
3y = 2x + 6
y = 2/3x + 2
2007-09-21 21:55:13
·
answer #1
·
answered by Jun Agruda 7
·
2⤊
0⤋
You need some points (x,y).
Pick a value for x.
Replace the 2x + 6 with whatever it becomes and work out what y is...
for example, use x=0. This means
2x + 6 becomes
2x0 + 6 which is 6.
So now 3y = 6 (when x is 0) which means that y is 2.
You used x=0 and got y=2 so (0, 2) is one point on your line.
Try at least two more values of x.
This type of equation is a straight line so if you get 3 points they should line up, if they don't then one is wrong.
2007-09-18 11:51:35
·
answer #2
·
answered by Anonymous
·
0⤊
1⤋
You can divide the entire equation by 3 which will give you y=(2/3)x+2. Then just make an x,y chart and solve for y when you assign x to be certain numbers. The use these points to sketch the line on a graph.
2007-09-18 08:41:16
·
answer #3
·
answered by darkangl494 3
·
0⤊
0⤋
3y=2x+6
y=2/3x+2
x -2 -1 0 1 2
y 2/3 1/3 2 5/3 7/2
and put these the x value on x-axis and y value on the y-axis and final u can get line.
2007-09-18 08:52:45
·
answer #4
·
answered by Anonymous
·
0⤊
0⤋
you use the usual drawing with x in abscissa and y in ordinates
then if you have x=0 you find 3y=6 and y=2 (this is a point on ordinate axis value 2 (we call it A))
you write y=0 then 0=2x+6 solving you have x=-3(this is a point on abscissa axis with value -3 (we call it B)
So, you have the two points A and B Draw a line between these 2 points
2007-09-18 08:46:24
·
answer #5
·
answered by maussy 7
·
0⤊
0⤋
rearrange to get y = ......
y = (2x + 6)/3
simplify
y = 2/3x + 2
compare to y = mx + c
where m = gradient and c = y axis intercept.
gradient = 2/3 and line crosses y axis at 2
gradient means for every 3 along (and right because positive) it goes 2 up
starting with pencil at x =0 y =2 draw a line that hits x = 3 y = 2
2007-09-18 20:59:37
·
answer #6
·
answered by hobgoblin 2
·
0⤊
1⤋
The answer is get the equation is your y=mx+b form, meaning have do you have to divide the term 3y by to get it to be y. At that point you can graph using a normal method. Just so you know you are going in the right direction b=2.
2007-09-18 08:41:15
·
answer #7
·
answered by waysj 3
·
0⤊
0⤋
first of all you need to make the equation equal to only y
so divide each side by 3:
y= 2/3x +6/3
=2/3x+2
this tells then tells you the y intercept is 2 following the formula
y=mx+c
where c is the y intercept and m is the gradient.
then if u simply substitute different numbers for x, you ll be able to plot a range of values, and then you can join them up to make a line:)
2007-09-18 08:42:19
·
answer #8
·
answered by two_quic 1
·
1⤊
0⤋
To draw a straight line a minimum of two points are required.
Two such points could be (0, 2) and (6 , 6)
Draw the line thro` these points.
2007-09-18 11:51:28
·
answer #9
·
answered by Como 7
·
2⤊
0⤋
2x + 6 = 3y------------- 1.
2x - 3y = - 6 !!!! This is how you form into a straight line . i bet you did learnt of algebraic expressions right ? this is some sort of like that . all you need to do is just change the postition of each number and finally you'll realized it . maths is the easiest of all . gambateh !
2007-09-18 09:38:27
·
answer #10
·
answered by cecilia_cwl 1
·
0⤊
0⤋