what the equation of the line perpendicular to the line 7x-4y=18, passing through the point (2, -1)?

Answer 1

4 y = 7 x - 18
y = (7 / 4) x - 18 / 4
m1 = 7 / 4
m2 = - 4 / 7
y + 1 = (- 4 / 7 ) ( x - 2 )
y + 1 = (- 4 / 7) x + 8 / 7
y = (- 4 / 7) x + 1 / 7

Answer 2

The situation of perpendicularity of two strains is the that the manufactured from their slopes is -one million.For the line 7x-4y=18 the equation could be written as -4y=-7x+18 or y= (7/4)*x-18 or the slope is 7/4. For line to be perpendicular the slope should be -4/7 so as that the product is -one million. The slope of line D & E is -4/7 and as a result the two those strains are perpendicular to line A yet to fulfill that this line additionally passes via factor (2,-one million) exchange the fee in the two equations. in common terms line E satisfies the equation whilst x=2 and y=-one million. Line D does not . as a result line E is the line perpendicular to line 7x-4y=18 and it additionally passes throught factor (2,-one million).

Answer 3

The product of the gradient of 2 perpendicular lines is always -1.

Simplifying 7x -4y = 18,

4y = 7x-18
y = 7/4x - 18/4

Since this equation is in the form y = mx+c where m is the gradient, the gradient of the given line is 7/4, and c is the y-intercept of the equation.

Letting a be the gradient of the perpendicular line,
m(7/4) = -1
m = -4/7

Hence we have the equation y = 4/7x + c -- (1)

Substituting (2, -1) into (1),
-1 =- 4/7(2) +c
c = 1/7

Therefore the equation desired is y = 4/7x + 1/7

Answer 4

To get the equation of a line perpendicular to a given line
ax + by = c, interchange the coefficients of x and y and change the sign of one of them. Change the constant c to k and find the value of the constant k from given additional condition.

Thus, equation of a line perpendicular to the given line
7x - 4y = 18 is 4x + 7y = k

To get the value of k, we use the given condition that the line passes through the point ( 2, - 1). Plugging (2, - 1 ) in the above equation,

4 (2) + 7 ( - 1 ) = k => k = 1.

Hence, the required equation is 4x + 7y = 1.

Answer 5

given the line 7x - 4y=18, convert this first into the standard form... y = mx + b

4y = 7x - 18
or
y = (7/4)x - 18/4

the slope of line is 7/4.

now, the line perpendicular to this line would have a slope that is negative reciprocal of 7/4 or -4/7

thus, the line perpendicular to it is
y = -(4/7)x + b

now, since the line should pass through (2,-1), we just substitute the values to solve for b.

-1 = (-4/7)*(2) + b
-1 = -8/7 + b
b = 8/7 - 1
b = 8/7 - 7/7
b = 1/7
thus the line is...

y = -(4/7)x + 1/7

Answer 6

the line 7x - 4y = 18 has slope = 7/4
So the slope of the perpendicular is -4/7
Equation of the perpendicular is
4x + 7y = 4 x 2 + 7 x (-1)
4x + 7y = 8 + (-7)
4x + 7y = 1

Answer 7

The given line has slope 7/4; since the line you want is perpendicular to the guven line, your line has slope -4/7. So, you are asked for the equation of the line through (2,-1) with slope -4/7. Use the point-slope form of the equation of a line.

Answer 8

slope of this line is 7/4, so slope of perpendicular m=-4/7
y=mx+c
y=-4x/7 + c
it passes through(2,-1)
-1=-8/7+c
1/7=c
substitue
y=-4x/7 + 1/7
resolving
4x + 7y=1

Answer 9

make y the subject:
4y= 7x-18
y=7x/4-9/2

now find the perpendicular gradient by -1 divided:
-1/(7/4)
-4/7

find equation:
y-2= -4/7(x+1)
y-2= -4/7x- 4/7
y= -4/7x +10/7