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lim as x approaches infinity of sqrt(x^2+4)/sqrt(4x^2+1)?

2007-09-17 21:14:36 · 4 answers · asked by ! 2 in Science & Mathematics Mathematics

4 answers

the answer is 1/2.. what you do is you divide the numerator and the denominator by sqrt(x^2), for the numertor, you get sqrt(1+4/(x^2)) and for the denominator you get sqrt(4+1/(x^2)) so with that, you're left with sqrt(1) over sqrt(4), which is 1/2

2007-09-17 21:25:47 · answer #1 · answered by nj 2 · 0 0

The answer is 1/2 because dividing the top and bottom by x^2 gives a fraction that tends to 1/4 as x tends to infinity and the sq root of 1/4 is 1/2

2007-09-18 04:25:20 · answer #2 · answered by Anonymous · 0 0

as x approaches infinity
the denominator, sqrt(4x^2+1), also approaches infinity
therfore the result approaches 0

2007-09-18 04:19:18 · answer #3 · answered by Pakyuol 7 · 0 0

Take the derivative of the numerator and denominator and apply L'Hospitals Rule.

Doug

2007-09-18 04:21:08 · answer #4 · answered by doug_donaghue 7 · 0 0

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