find cosx and tanx if sinx=3/5?

Answer 1

Assuming that you are talking about an acute angle

cos(x) = sqrt(1 - sin^2(x)) = 4/5
tan(x) = sin(x) / cos(x) = 3/4

If you do not confine x to the first quadrant:
cos(x) = ±4/5
tan(x) = ±3/4

sin(x) is positive.
cos(x) and tan(x) must have the same sign.

Answer 2

there are two possible values for cosx. they are 4/5 and -4/5.same goes for tanx...the two possible values are 3/4 and -3/4...
if x is located at quadrant 1...cos x = 4/5 and tan x = 3/4
if x is located at quadrant 2...cos x = -4/5 and tan x = -3/4

Answer 3

sin²+cos²=1
9/25+cos²=1
cos²=16/25
cos=±4/5

tan = sin/cos = 3/5÷±4/5=±3/4

Answer 4

You really --really-- need to learn the trig function definitions.
sin(x) = 3/5 => cos(x)= 4/5 (WHY???)
tan(x)=sin(x)/cos(x)=3/4

Doug