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AB=12
AD=20
angle A=30
I don't know how to set this problem up.

2007-09-17 15:52:51 · 8 answers · asked by Jen 4 in Science & Mathematics Mathematics

8 answers

AB = 12
AD = 20
Angle BAD = 30°
Perpendicular height = h
h = AB sin 30°
h = 12 x 0.5 = 6
Base = AD = b = 20
Area = b h
Area = 20 x 6 units ²
Area = 120 units ²

2007-09-18 04:25:44 · answer #1 · answered by Como 7 · 1 2

The set up is not complicated. The area of a parallelogram, A, is equal to the measurement of the base times the measurement of the height.

ABCD is a parallelogram, but not a rectangle: ang (A)=30 deg. Crucial step is to determine the height of ABCD. THE HEIGHT IS NEITHER 12 NOR 20. Draw a segment perpendicular to BC. The perpendicular segment through B forms a nice right triangle (30-60 right triangle): finding the height should be easy from here.

2007-09-17 23:11:00 · answer #2 · answered by john s 3 · 0 2

first determine the height:

h= AD.cos(90-30) = AD.cos(60) = 20.(1/2) = 10

Base = AB = 12

Area = Base.height = AB.h = 12*10 = 120

take a look at this link:

http://www.mathgoodies.com/lessons/vol1/area_parallelogram.html

* * * * * Explanation

1 - project from point D to segment AB the height to intersect a point H.
2- angle of ADH = 180 - 90 - 30 = 60
3- h= DH = AD.cos(angle ofADH) = 20.cos(60) = 20.(1/2) = 10
4 - Area = Base.height = AB.h= 12*10 = 120

2007-09-17 23:01:09 · answer #3 · answered by aspx 4 · 0 2

Draw the segment BD. This splits the parallelogram into 2 congruent triangles. Congruent triangles have equal areas.

You're given SAS for triangle ABD. Use the area formula, A = 1/2*b*c*sin(A), where A is the angle between segments b and c.

You have the area for triangle ABD, which is the same as the area for triangle CBD. Add those (or just double the initial area) and you're set.

2007-09-17 23:02:32 · answer #4 · answered by np_rt 4 · 0 2

ok the area is A=B*H
where A=area
B=Base
H=Height
So
A= 12*20=
I am not sure which one is base and height depends on the direction but the answer will still be the same

The information for the angle is just used for you to draw the parallellogram
angles

http://www.mathgoodies.com/lessons/vol1/area_parallelogram.html

2007-09-17 23:05:40 · answer #5 · answered by mnbengr 1 · 0 2

the area of a parallelogram is simply base times height

if ϑ is 30, use trig to find the height. more specifically, cos(30)*20 will give the height, which you just multiply by 12

it's simple if you draw it out

2007-09-17 23:01:14 · answer #6 · answered by Davies 3 · 1 2

nothing to set up!!!
area of a parallelogram = product of 2 consecutive sides and sin of included angle.

2007-09-17 22:57:20 · answer #7 · answered by swd 6 · 0 1

if one side is 12, another is 20. since its a p-gram, 12 and 20 is the length of the other two.12x20=240

2007-09-17 22:57:41 · answer #8 · answered by Harris 6 · 0 2

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