Please answer this ten point chemistry question!?

Question

How many grams of CuSO4 * 5H20 are needed to prepare 100 mL of a .10 M solution?

Answer 1

MW of CuSO4.5H2O = 249.5

To prepare 1000 ml of 0.10 M solution,
amt needed = 0.1 * 249.5 = 24.95 g

For 100 ml,
amt needed = (100/1000) * 0.1 * 249.5 = 2.495 g

Answer 2

100 mL of a .10 M solution provides 0.01 moles of the salt CuSO4. So calculate the mole wt of the hydrated salt and multiply by 0.01 to get grams.