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An object has an initial velocity of magnitude of 15 m/s to 30° north of east. It is subjected to the forces:
F(1) = 20 N(newtons), 40° south of east.
F(2) = 80 N, 20° west of north.

Motion is detected by adding the force vectors and finding the Net Force. The Accel is the net force vector divided by the objects mass (2 kg).
After 4 seconds find:
A. magnitude of displacement. |x|
B. direction of displacement.
C. magnitude of velocity.
D. direction of velocity.

2007-09-17 15:46:57 · 1 answers · asked by johnnyboy 2 in Science & Mathematics Physics

These are my calculations so far:
F(1) = ( 20cos40°, -20sin40°)
F(2) = ( -80sin20°, 80cos20°)
F(net) = ( -12.04, 62.32)
|F(net)| = 61.14 {distance formula}

Not sure what to do next.

2007-09-17 15:52:43 · update #1

1 answers

Vector math allows you to deal with the x and y components separately. (Let's call them the "east" and "north" components to avoid confusion with the displacement vector, which is apparently called "x" in this problem).

So, first figure out the final eastward velocity and final eastward displacement, based on the initial eastward velocity and the total eastward force. (The "total eastward force" is the sum of the eastward components of F(1) and F(2).)

Then, do the same thing for the "north" components.

Then:

A: sqrt(east² + north²)
B: Tan(θ) = east/north
C: sqrt(v_east² + v_north²)
D: Tan(α) = v_east / v_north

2007-09-17 16:09:29 · answer #1 · answered by RickB 7 · 0 0

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