42 - 7y + 3y = - 6
-7y + 3y = - 6 - 42
- 4y = - 48
4y = 48
y = 12
2007-09-18 04:38:27
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answer #1
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answered by Como 7
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Solve for the "y" variable.... 42-7y = -3y-6
First: combine terms with the same variable - add 3y to both sides (when you move a term to the opposite side, always use the opposite sign).
42-7y+3y = -3y+3y-6
42-7y+3y = - 6
42 - 4y = - 6
SEc: subtract 42 from both sides...
42 - 42 - 4y = - 6 - 42
- 4y = - 6 - 42
- 4y = - 48
Third: solve for "y" by isolating it - divide both sides by -4.
- 4y/-4 = - 48/-4
y = - 48/-4
y = 12
2007-09-17 15:48:05
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answer #2
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answered by ♪♥Annie♥♪ 6
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If you get all the "y" terms on one side and all the constant (number) terms on the other, you should be okay.
42-7y=-3y-6
adding 3y to both sides
42-4y=6
subtract 42 from both sides
-4y=-36
y=9
check your work
42-7(9) should equal 3(9)-6
42-63=21 and 27-6 equals 21 so answer is correct
2007-09-17 15:47:35
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answer #3
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answered by cgflann 4
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42-7y=-3y-6
42=4y-6
48=4y
12=y
Plugging this in for y gives -42 on both sides, so it checks.
2007-09-17 15:52:55
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answer #4
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answered by james w 5
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42-7y = -3y-6
add 7y to both sides
42 = 4y - 6
add 6 to both sides
48 = 4y
divide both sides by 4
y = 48/4
y = 12
2007-09-17 15:45:54
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answer #5
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answered by Pakyuol 7
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42 - 7y = - 3y - 6
+ 6
48 - 7y = - 3y
+ 7y
48 = 4y
/4
y = 12
2007-09-17 15:46:03
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answer #6
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answered by Anonymous
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hey ty. move -3y to the left. so its +3y.
42 to the other side so its -42.
3y-7y=-6-42
-4y=-48
4y=48
y=48/4=12
2007-09-17 15:48:50
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answer #7
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answered by Harris 6
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42-7y=-3y-6
42+6 = 7y-3y
48 = 4y
y = 12
2007-09-17 15:46:19
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answer #8
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answered by tj is cool 5
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add 7y to both sides - you want to get all the y's on one side.
42 = 4y - 6
now add 6 to both sides
48 = 4y
now divide by 4 on both sides
12 = y
2007-09-17 15:46:17
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answer #9
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answered by ccw 4
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42 - 7y = -3y - 6 ... add 6 to both sides
48 - 7y = -3y ... add 7y to both sides
48 = 4y ...divide both sides by 4
12 = y
2007-09-17 15:46:29
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answer #10
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answered by Danny G 2
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