G(5-3) would be solving for G(2). G(5) - G(3) u solve each in independently then subtract the two answers.
2007-09-17 15:42:50
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answer #1
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answered by Danny G 2
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They do NOT generally end up with the same answer.
Example: suppose g(x) = x² + 4
g(5-3) = g(2) = 2² + 4 = 8
But:
g(5) = 5² + 4 = 29
g(3) = 3² + 4 = 13
g(5) - g(3) = 29 - 13 = 16
So, there you have a specific example where g(5) - g(3) does not equal g(5-3).
2007-09-17 22:51:47
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answer #2
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answered by RickB 7
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g(5 - 3) means that you plug "(5 - 3)" in to the function g.
g(5) - g(3) means that you plug 5 into the function g, and then you plug 3 into the function g, and then you take the difference.
For example, if g(x) = x^2, then
g(5 - 3) = (5 - 3)^2 = 2^2 = 4
g(5) - g(3) = 5^3 - 3^2 = 25 -9 = 16.
So g(5 - 3) and g(5) - g(3) need not be the same thing (and, in fact, they usually aren't).
2007-09-17 22:45:52
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answer #3
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answered by Anonymous
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Hi,
g() is some function.
g(5-3) means, "do g() to 5-3" or, "do g() to 2"
g(5) - g(3) means:
"do g() to 5 and subtract from the result whatever you get when you do g() to 3"
For example, let's just say g(x) = x^2
g(5-3) = (5-3)^2 = 2^2 = 4
g(5) - g(3) = 5^2 = 3^2 = 25 - 9 = 16
hth.
REgards,
Chas.
2007-09-17 22:45:16
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answer #4
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answered by Chas. 3
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It is not the same. Consider this example:
g(x) = x^2
g(5-3) = g(2) = 2^2 = 4
But,
g(5) = 5^2 = 25, and g(3) = 3^2 = 9
So,
g(5) - g(3) = 25 - 9 = 16
So, it is clear that it is not the same thing.
2007-09-17 22:48:06
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answer #5
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answered by Christine P 5
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well have you tried plugging numbers into your eqution? does 5(5-3) which equals 10 is that equal to 5(5) - 5(3) which equals 25-15=10? there is your answer
2007-09-17 22:45:47
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answer #6
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answered by D 2
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distributive property of multiplication
2007-09-17 22:45:49
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answer #7
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answered by ferdie 2
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