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Functions question - do they end up with the same answer or is there a different way they're done?

2007-09-17 15:39:09 · 7 answers · asked by Bo 3 in Science & Mathematics Mathematics

7 answers

G(5-3) would be solving for G(2). G(5) - G(3) u solve each in independently then subtract the two answers.

2007-09-17 15:42:50 · answer #1 · answered by Danny G 2 · 1 0

They do NOT generally end up with the same answer.

Example: suppose g(x) = x² + 4

g(5-3) = g(2) = 2² + 4 = 8

But:
g(5) = 5² + 4 = 29
g(3) = 3² + 4 = 13
g(5) - g(3) = 29 - 13 = 16

So, there you have a specific example where g(5) - g(3) does not equal g(5-3).

2007-09-17 22:51:47 · answer #2 · answered by RickB 7 · 0 0

g(5 - 3) means that you plug "(5 - 3)" in to the function g.

g(5) - g(3) means that you plug 5 into the function g, and then you plug 3 into the function g, and then you take the difference.

For example, if g(x) = x^2, then

g(5 - 3) = (5 - 3)^2 = 2^2 = 4

g(5) - g(3) = 5^3 - 3^2 = 25 -9 = 16.

So g(5 - 3) and g(5) - g(3) need not be the same thing (and, in fact, they usually aren't).

2007-09-17 22:45:52 · answer #3 · answered by Anonymous · 0 0

Hi,

g() is some function.

g(5-3) means, "do g() to 5-3" or, "do g() to 2"

g(5) - g(3) means:
"do g() to 5 and subtract from the result whatever you get when you do g() to 3"

For example, let's just say g(x) = x^2

g(5-3) = (5-3)^2 = 2^2 = 4

g(5) - g(3) = 5^2 = 3^2 = 25 - 9 = 16

hth.

REgards,
Chas.

2007-09-17 22:45:16 · answer #4 · answered by Chas. 3 · 0 0

It is not the same. Consider this example:

g(x) = x^2

g(5-3) = g(2) = 2^2 = 4
But,
g(5) = 5^2 = 25, and g(3) = 3^2 = 9
So,
g(5) - g(3) = 25 - 9 = 16

So, it is clear that it is not the same thing.

2007-09-17 22:48:06 · answer #5 · answered by Christine P 5 · 0 0

well have you tried plugging numbers into your eqution? does 5(5-3) which equals 10 is that equal to 5(5) - 5(3) which equals 25-15=10? there is your answer

2007-09-17 22:45:47 · answer #6 · answered by D 2 · 0 0

distributive property of multiplication

2007-09-17 22:45:49 · answer #7 · answered by ferdie 2 · 0 0

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