geometry. show that the converse of each conditional is false. problem x=-5, then x2 (squared)=25?

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geometry. show that the converse of each conditional is false. problem x=-5, then x2 (squared)=25?

2007-09-17 15:38:08 · 4 answers · asked by VICKI K 1 in Science & Mathematics ➔ Mathematics

4 answers

Hi.

The converse is that if x^2 = 25, then x = -5

However, 5^2 = 25, but 5 != -5

REgards,
Chas.

2007-09-17 15:42:01 · answer #1 · answered by Chas. 3 · 0⤊ 0⤋

The statement:
if x = -5 then x^2 = 25
is true
(verify by multiplying (-5)*(-5) )

The converse:
If x^2 = 25 then x = -5
is not true
because we can find
x=+5 such that x^2 = 25

So it could be that x^2 = 25 leads to x = +5, contrary to our converse.

2007-09-17 22:43:29 · answer #2 · answered by Raymond 7 · 0⤊ 0⤋

x= -5
x2( square )=25

usually
x2 ( square ) =25
then x = +/- 5 ( plus or minus )

2007-09-17 23:09:46 · answer #3 · answered by Anonymous · 0⤊ 0⤋

its true.

2007-09-17 22:42:01 · answer #4 · answered by Harris 6 · 0⤊ 0⤋