Math Help (Word Problem)?

Question

Can you please explain it too...
Find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 82.

Answer 1

let x = 1st odd integer

so the 2nd consecutive integer = x+2
the 3rd consecutive integer = x+2+2 = x+4

...the sum of the first, two times the second, and three times the third is 82...
x + 2(x+2) + 3(x+4) = 82
x + 2x + 4 + 3x + 12 = 82
x+2x+3x = 82-4-12
6x = 66
x = 11

integers = 11, 13, 15

Answer 2

Three consecutive odd integers x, x+2, x+4
x +2(x+2) + 3(x+4) = 82
x + 2x + 4 + 3x + 12 = 82
6x + 16 = 82
6x = 66
x = 11
The integers are 11, 13, and15

Answer 3

Let x be the first integer
x+2 is the next integer
x+4 is the thrid.
So x+2(x+2)+3(x+4)= 82
or 6x +16=82
x=11.

Answer 4

you wrote the question wrong...it's incomplete. 2 times the second and three times the third is not going to equal 82 on any consecutive odd integers...please rephrase

Answer 5

let (2n+1), (2n+ 3) and (2n + 5) are three consecutive odd numbers

2n+ 1 + 2(2n+3) + 3(2n + 5) = 82
2n+1 + 4n + 6 + 6n +15 = 82
12n + 22 = 82
12n = 60
n = 60/12 = 5
so the numbers are
11, 13, 15

Answer 6

Hi.

let's use:
1st number: x
2nd number: x+2
3rd number: x+4

so....
x + 2(x+2) + 3(x+4) = 82
x + 2x + 4 + 3x + 12 = 82
6x + 16 = 82
6x = 66
x = 11

So, you numbers are: 11, 13, 15

hth.

REgards,
Chas.

Answer 7

numbers are x,x+2,x+4
x+2(x+2)+3(x+4)=82
6x=82-16
x=11
therefore the numbers are 11,13and15