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Why are the outer-most electrons the only ones included in the orbital filling diagram and the electron dot diagram?

2007-09-17 15:31:04 · 3 answers · asked by IN0C3NT 2 in Science & Mathematics Chemistry

3 answers

In theory they should be, however when dealing with very large atoms, or lots of atoms it would be very difficult to draw every single electron in. Also, in almost all reactions it is only the outermost electrons that will be involved in a reaction, in these terms the distance between two shells can be thought of as quite large, so the energy needed to break though into a lower shell would be very great.
Therefore it is common practise to ignor all but the outer most shell, as this is the one of intrest in the chemical reaction.

2007-09-17 15:46:45 · answer #1 · answered by Anonymous · 0 0

The energy to remove an electron from a full inner shell to an outer orbital is too high to be recovered by the ensuing reaction. Thus, the removal doesn't occur.

2007-09-17 15:35:47 · answer #2 · answered by cattbarf 7 · 0 0

[Ar] 3d10 4s2 4p4 2 electrons interior the 4p orbital are unpaired the reason being via properties of ways electron shells fill. in case you comprehend what the Aufbau concept is, or Hund's rule, those could be utilized to describe the order that the electrons fill. THERE ARE 2 UNPAIRED ELECTRONS, not 4! The 4p orbital feels like this [i!][i][i] the place the "i" and "!" are electrons

2016-12-17 03:56:48 · answer #3 · answered by ? 4 · 0 0

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