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in other words, what does g equal? is it something like g=1/2*v*t^2 or something???

2007-09-17 14:49:30 · 4 answers · asked by Anonymous in Science & Mathematics Physics

4 answers

it depends on what variables you know.

for example

d = Vot + 1/2 a t^2

if you know d, and drop an object at rest and measure t, then...

d = 0 x t + 1/2 a t^2
d = 1/2 a t^2
a = 2d/t^2

a, by the way is acceleration. in the special case of gravity, a = g

g does not ever = 1/2 v t^2. the units would be m/s x s^2 = mxs

g has units m/s^2

2007-09-17 14:59:33 · answer #1 · answered by Dr W 7 · 1 0

Near the surface of the Earth, you don't need any equation at all. The acceleration of gravity is simply 9.81 meter/second^2.

2007-09-17 14:54:13 · answer #2 · answered by lithiumdeuteride 7 · 0 0

there is no equation, just a constant (I suppose it does vary ever so slightly with distance from sea level)

g=9.81 m/s/s (m/s^2)
(I think more accurately it is something like 9.80655.

there is another equation for velocity after the passage of time under a constant acceleration, is that what you mean?

2007-09-17 14:56:43 · answer #3 · answered by Anonymous · 0 0

9.8m/s^2 or in terms of force is 9.8 N/kg per 1 kg

2007-09-17 14:55:59 · answer #4 · answered by Este_Esco 2 · 0 0

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