A rock climber throws a small first aid kit to another climber who is higher up the mountain. The initial velocity of the kit is 24 m/s at an angle of 52° above the horizontal. At the instant when the kit is caught, it is traveling horizontally, so its vertical speed is zero. What is the vertical height between the two climbers?
m
2007-09-17 14:01:10 · 2 answers · asked by Marianna E 1 in Science & Mathematics ➔ Physics
When the vertical speed is zero, it is at apogee so
vy(t)=0=24*sin(52)-g*t
solve for t and plug into
y(t)=.5*24*sin(52)*t^2 to find the distance
j
2007-09-17 14:20:43 · answer #1 · answered by odu83 7 · 0⤊ 0⤋
For the vertical component of the system,
a=-9.81
u=24 sin52
v=0
s=what you want to find.
Use the formula v^2=u^2+2as
You should be able to find the answer.
2007-09-17 21:19:23 · answer #2 · answered by monkey 2 · 0⤊ 0⤋