Many tire manufacturers guarantee their tires for 50,000 miles. If a tires has a 16 in radius, how many revolutions of the tires are guaranteed? There are 63,360 inches in a mile. Round to the nearest revolution.
2007-09-17 13:56:19 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
FIRST FIND THE CIRCUMFERENCE OF THE TIRE... THE CIRCUMFERENCE WILL ALSO = 1 REVOLUTION....
c= 2PI(R)
C = 2(3.14)(16IN) = 100.48 IN
NEXT FIGURE OUT HOW MANY INCHES IS IN 50,000 MILES....
50,000 MILES x 63,360 IN/MILE = 3,168,000,000
FINALLY IF YOU DIVIDE THE NUMBER OF INCHES IN 50,000 MILES BY THE CIRCUMERFENCE OF THE TIRE YOU WILL FIND THE NUMBER OF REVOLUTIONS THE TIRE COMPANY GARENTEES....
3,168,000,000 IN
------------------------
100.48 IN
31528662.420...
ROUND TO THE NEAREST REVOLUTION YOU GET....
31,528,662 REVOLUTIONS
2007-09-17 14:07:24 · answer #1 · answered by googooslide2000 3 · 0⤊ 0⤋
5280 feet in a mile
16/6 feet is diameter
I divided by 6 instead of 12.
This effectively multiplies by 2.
Radius doubled is diameter.
3.14159265358979323846 is pi.
Diameter times pi is AroundDistance.
16/6 is 8/3 is (8+8)/(3+3).
8/3 is 2 and 2/3 because 2 is 6/3.
6 + 2 is 8 and 8/3 is (6+2)/3 and 6/3 is 2.
So 2 and 2/3 is about 2.6666667
So the AroundTheTireDistance is
8.377580408 feet.
Because 8.377580408 / 3.14159265 is
8/3 feet or 32/12 feet or 32 inches.
Now 50000 miles is how many feet?
50000 miles
x 5280 feet in a mile
_______
264000000 feet miles in a mile
feet miles in a mile is
just feet because mile/mile is one.
Now "feet the tire will go"
divided by "feet in a rotation" will
give you "feet tire go per feet in turn".
This somehow gives just "# of turns".
31512678.7 turns of the tire before
it wears out.
2007-09-17 21:12:50 · answer #2 · answered by winter_new_hampshire 4 · 0⤊ 0⤋
Circumference of a 16 inches radius tyre
=2*pi*16
=2*3.14*16
=100.48 inches
Therefore revolutions in traveling 50,000 miles
=50,000*63,360/100.48
=3152866.20
2007-09-17 21:05:59 · answer #3 · answered by alpha 7 · 0⤊ 0⤋
You know how many inches are in 1 mile, so figure out how many are in 50,000 miles. When a tire rolls through 1 revolution, it travels forward the number of inches that equal the tire's circumference.
A tire's circumference is pi*2*radius. So once you find out how many inches are in one revolution, you can figure out how many revolutions would equal the total number of guaranteed inches.
2007-09-17 21:00:10 · answer #4 · answered by Anand S 3 · 0⤊ 0⤋
Circumference = pi. diameter = 2 pi.radius = 2 x 3.1416 x 16 = 100.531 approx.
So, number of revolutions (assuming no slip and sliding) is
50,000 x 63, 360 / 100.531 = 31512667.7 = 31512668 revolutions
2007-09-17 21:04:25 · answer #5 · answered by Swamy 7 · 0⤊ 0⤋
C = 2 * pi * r
Each C = 1 Rev
Number of Revs = miles * inches/mile * 1 rev/circumference
2007-09-17 21:03:56 · answer #6 · answered by sheramcgyver 2 · 0⤊ 0⤋
1 rev = 2 Ï r
1 rev = 2 Ï (16) ins
1 rev = 32 Ï ins
No. of revs
= (50,000 x 63,360) / 32 Ï
= 5 x 63,360 x 10^4 / 32 Ï
= 3151 x 10^4
= 31,510,000
2007-09-18 03:09:42 · answer #7 · answered by Como 7 · 1⤊ 1⤋
1 revolution = 2pir = 32pi imches
So 50,000*63360/32pi= 31,512,679 revolutions
2007-09-17 21:06:13 · answer #8 · answered by ironduke8159 7 · 1⤊ 0⤋
63360X50000/32pi=31512678.732195285046896828593642
so 31512679
2007-09-17 21:01:52 · answer #9 · answered by Anonymous · 0⤊ 0⤋
10000 i think?
2007-09-17 21:01:10 · answer #10 · answered by ஐ♦♠♣♥abercrombie♥♣♠♦ஐ 3 · 0⤊ 0⤋