Help with this problem? twister?

Question

This problem is so twisted. I tried like three times but could not get it:
The length of a rectangle is twice its width "w". A second rectangle, which is 8 cm longer and 3 cm marrower than the first rectangle, has perimeter 154 cm. Find the dimensions of each triangle.
Explain to me please? And do not call me stupid!

Oh, lol, i'm so sorry, (now i really seem stupid), i meant rectangle for all of em.

Answer 1

I think you mean, Find the dimensions of each *rectangle*.

Let
For the first rectangle
L = length
W = width

L = 2W

For the second rectangle
L + 8 = length
W - 3 = width
P = perimeter
________


P = 2[(L + 8) + (W - 3)] = 154
(L + 8) + (W - 3) = 77
L + W = 72
2W + W = 72
3W = 72

W = 24
L = 2W = 2*24 = 48

The first rectangle is 24 cm by 48 cm.

L + 8 = 48 + 8 = 56
W - 3 = 24 - 3 = 21

The second rectangle is 21 cm by 56 cm.

Answer 2

Say that L is the length of the first rectangle, and W is its width.
For the second rectangle, the perimeter is 2(L+8) + 2(W-3) = 154.
And since L = 2W, this gives 2(2W+8) + 2(W-3) = 154.
Solve for W to get W = 24 (You do the work!)
so original rectangle is 48 x 24, second rectangle is 56 x 21.

Answer 3

We'll say that the first rectangle is L=2W

So the second rectangle would be:
2(2W+8)+2(W-3)=154
(4W+16)+(2W-6)=154
6W+10=154
6W=144
W=24

So the origional rectangle was 48 by 24

Answer 4

FIRST RECTANGLE....
WIDTH = W
LENGTH = 2 X THE WIDTH = 2W

THE SECOND RECTANGLE....
LENGTH = 8 CM LONGER THAN THE FIRST RECTANGLES LENGTH... THE FIRST RECTANGLES LENGTH = 2W SO....
LENGTH = 2W + 8
WIDTH = 3 CM NARROWER THAN THE WIDTH OF THE FIRST RECTANGLE... THE FIRST RECTANGLESWIDTH IS W.... SO....
WIDTH = W - 3

SUM IT UP...
THE SECOND RECTANGLES DIMENSIONS ARE....
LENDTH = 2W + 8
WIDTH = W - 3

YOU NOW THE FORMULA OF A RECTANGLE IS...
P = 2L + 2W WHERE...
P = PERIMETER
L = LENGTH
W = WIDTH....
SO SUBSTITUTE INTO THE FORMULA...

154 = 2(2W + 8) + 2(W - 3)
154 = 4W + 16 + 2W - 6
154 = 6W + 10
144 = 6W
24 = W

RECALL:
DIMENSIONS OF RECTANGLE 1:
WIDTH = W
LENGTH = 2W

DIMENSIONS OF RECTANGLE 2:
LENDTH = 2W + 8
WIDTH = W - 3

SUBSTITUTE IN W = 24 AND YOU WILL HAVE THE DEMINSIONS OF BOTH RECTANGLES....

DIMENSIONS OF RECTANGLE 1:
WIDTH = (24)
LENGTH = 2(24) = 48

DIMENSIONS OF RECTANGLE 2:
LENDTH = 2(24) + 8 = 48 + 8 = 56
WIDTH = (24) - 3 = 21

SO TO SUM IT UP....

DIMENSIONS OF RECTANGLE 1:
WIDTH = 24
LENGTH = 48

DIMENSIONS OF RECTANGLE 2:
LENDTH = 56
WIDTH = 21

Answer 5

Ok.....well first....ask the question properly.

Are we talking rectangles or triangles!?