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c/5a = c + b/ac
solve for a
a=?

2007-09-17 13:12:07 · 4 answers · asked by dreamz 4 in Science & Mathematics Mathematics

4 answers

c/5a=c+b/ac
Multiply both side by a.
so we get
c/5=ac+b/c............now
c/5-b/c=ac..............solve this
(c^2-5b)/5c=ac..........^...means square...........now taking c to denominator it gives a value..
a=(c^2-5b)/5c^2

Best of luck mate

2007-09-17 13:40:47 · answer #1 · answered by blu u 1 · 0 0

c/5a = c + b/ac
solve for a
a=?

solution
c/5a = c + b/ac
c=5ac + 5ab/ac
c=5ac + 5b/c
5ac=c - 5b/c
a= (c - 5b/c)/5c
a=1/5 - 5b/5c^2
a=1/5 - b/c^2

2007-09-17 20:28:42 · answer #2 · answered by ahchuan122 1 · 0 0

c / 5a = c + b/ac

The LCM of 5a and ac is 5ac, so this equation is equivalent to

c^2 / 5ac = 5ac^2/ 5ac + 5b / 5ac

Multiplying both members by 5ac,

c^2 = 5ac^2 + 5b

c^2 - 5b = 5ac^2

(c^2 - 5b) / 5c^2 = a

2007-09-17 20:26:55 · answer #3 · answered by jcastro 6 · 0 0

solve ur own questions

2007-09-17 20:23:03 · answer #4 · answered by Anonymous · 0 2

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