A certain copper wire has a resistance of 9.8 . At what point along its length must the wire be cut so that the resistance of one piece is 6.0 times the resistance of the other?
1/5 of the length
1/6 of the length
1/7 of the length
****Here I have determined that 1/7 of the length is the correct answer as follows:
6x=L-x
7x=L or 1/7
The book does not give formulas or have similar problems of the following. Help with formulas and calculations would be greatly appreciated.
What is the resistance of each piece?
A) larger piece
B)smaller piece
2007-09-17 13:01:18 · 1 answers · asked by Jessie L 2 in Science & Mathematics ➔ Physics
Clearly one seventh of the length would have one seventh of the resistance. And six sevenths of the length would have six sevenths of the resistance.
A.) R = (6/7)(9.8) = 8.4 ohms
B.) R = (1/7)(9.9 = 1.4 ohms
2007-09-17 13:13:19 · answer #1 · answered by jsardi56 7 · 0⤊ 0⤋