1/9 - 2/3b = 1/18
can someone please explain me how to solve this problem step by step?
2007-09-17 12:39:36 · 6 answers · asked by Anon2250 2 in Science & Mathematics ➔ Mathematics
they are in fractions
2007-09-17 12:45:33 · update #1
assuming 1/9 - (2/3)b = 1/18
1/9 - 1/18 = (2/3)b
(2-1)/18 = (2/3)b
1/18 = (2/3)b
1/18 * 3/2 = b
b = 1/12
if 1/9 - 2/(3b) = 1/18...
1/9 - 1/18 = 2/(3b)
(2-1)/18 =2/(3b)
1/18 = 2/(3b)
3b = 2(18)
b= 2(18)/3
b=12
2007-09-17 12:50:16 · answer #1 · answered by Simple Mind 4 · 0⤊ 0⤋
When you write 2/3b, does it mean (2/3) b, or 2/ (3b)?
I will assume you mean (2/3) b.
First, change it all the 1/18-ths:
2/18 - 12/18 b = 1/18
Multiply both sides by 18
2 - 12b = 1
Subtract 1 from each side
1 - 12b = 0
Therefore, 1 = 12 b
Divide each side by 12
b = 1 / 12
2007-09-17 19:46:23 · answer #2 · answered by morningfoxnorth 6 · 0⤊ 0⤋
Is the second term 2/(3b) or (2/3)b ?
2007-09-17 19:44:39 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
ok first make them commen dondmeters in this case 18 so you have
2/18 - 10/18b =1/18 then you subract 2/18 from both sides and you have
-10/18b=-2/18 then you solve
2007-09-17 19:48:07 · answer #4 · answered by nice cute chick 2 · 0⤊ 0⤋
it its (2/3)b, b=1/12
If its 2/(3b), b =12
2007-09-17 19:46:15 · answer #5 · answered by Anonymous · 0⤊ 0⤋
subtract 1/9 from both sides
multiply both sides by -3/2
This will give you b = 1/12, I think.
2007-09-17 19:46:13 · answer #6 · answered by Bob S 2 · 0⤊ 0⤋