their a system.
i graphed n thought that they intersectid @ (1.75, -.25) but when i checked it it didn't check for the 2nd equation. wat i'd do wrong?
2007-09-17 12:37:44 · 4 answers · asked by [xo♥ox] 1 in Education & Reference ➔ Homework Help
solve this by adding.
3x+y=5
x-y=7
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4x = 12 (y's cancel out)
divide by 4
x = 3
to solve for y, plug the value of x (3 ) into any of the two equations:
3(3) + y = 5
9 + y = 5
subtract 9
y = -4
(3, -4)
2007-09-17 12:44:27 · answer #1 · answered by vaiogirl 3 · 0⤊ 0⤋
I think it would be easier just to add the two equations than to graph them.
3x + y = 5
+ x - y = 7
-------------
4x = 12
You should be able to solve it from there.
2007-09-17 19:44:07 · answer #2 · answered by MinaMay 4 · 0⤊ 0⤋
x = 7 - y; given
3(7-y) + y = 5
21 - 3y + y = 5
-2y = -16
y = 8
x = 7 - y; given
x = 8 - 7
x = 1
2007-09-17 20:20:46 · answer #3 · answered by Steve B 6 · 0⤊ 0⤋
x=3
y=-4
2007-09-17 19:44:50 · answer #4 · answered by Anonymous · 0⤊ 0⤋