David is driving a steady 29.0 m/s when he passes Tina, who is sitting in her car at rest.?

Question

Tina begins to accelerate at a steady 2.30 m/s^2 at the instant when David passes.
How far does Tina drive before passing David?
What is her speed as she passes him?

Answer 1

Time to cross David is 25.217 seconds.

Distance driven is 731.28 meters.

Answer 2

The equations are
x(t)=29*t for David
and
x(t)=.5*2.3*t^2 for Tina

when they are equal, they pass.
note that t=0 is a solution per the problem statement

the other solution is
t=2*29.0/2.3
25.2 seconds

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