Can someone do these two math problems for me? I'm having trouble. Explain too please?

Question

V= pi/3 times r squared times h
solve for h

and



S=L(1-r)
solve for r


Thanks, they probably really easy but, I can't do them. Please explain how you go the answer.

Answer 1

Problem 1) V = (Pi/3)*h*r^2

You want h = something so that means you want h on one side of the equal sign and everything else on the other.

Divide both sides by r^2: V/(r^2) = (Pi/3)h
Multiply both side by 3: 3V/(r^2) = (Pi)h
Divide both sides by Pi: 3V/((Pi)(r^2) = h

You'll get
h = 3V/((Pi)(r^2))

That's h equals 3 times V divided by the quantity (Pi)(r^2)

Problem 2: S = L(1-r)
Divide both sides by L you get: S/L = 1-r
Add r to both sides you get: (S/L)+r = 1
Now subtract (S/L) from both sides you get: r = 1 - (S/L)

Final answer: r = 1 - (S/L)

Answer 2

ok here's what i got:

H= pi/3 times r squared times v

and

r=L-s

For the first one all you have to do is trade places with h and v and it will equal the same thing.
For the second one multiply out the numbers in the parenthesis and so it is:
s= L-r
add r to both sides
r+s=L
and then subract s from both sides to get r alone.
r= L-s
I hope this made sense! Lol

Answer 3

make h the subject of the formula by dividing V by everything else on that side [remember dividing by pi/3 is the same as multiplying by 3/pi]
so you get 3V/pi [r squared] = h

for this, divide by L first: S/L=(1-r)
then - 1 from both sides, :S/L -1= -r
then reverse the signs of everything
: 1-S/L =r