A biker speeds up to 26.2 m/s from rest in 5.36 seconds. The biker maintains this speed for 6.57 seconds befor

Question

(a) What was the biker's average speed (in m/s) for the trip?
m/s




(b) Could you have just added the average speed values for the 3 different sections of the trip above and divided by 3 to get the correct answer? Please explain fully.

A biker speeds up to 26.2 m/s from rest in 5.36 seconds. The biker maintains this speed for 6.57 seconds before coasting to a stop in 4.33 seconds. THATS THE FULL INTRO SRY

Answer 1

v1(final) = 26.2; t1 = 5.36; t2 = 6.57; t3 = 4.33
v1(ave) = v1(final)/2; x1 = v1(ave)t1
v2(ave) = v1(final); x2 = v2(ave)t2
v3(ave) = v1(final)/2; x3 = v3(ave)t3
x(tot) = x1+x2+x3
t(tot) = t1+t2+t3
(a): v(ave) = x(tot)/t(tot)
(b): No. Each speed has an effect on the average speed that is proportional to its duration. Simple averaging doesn't account for this. The expansion of the (a) answer,
v(ave) = (v1(ave)t1+v2(ave)t2+v3(ave)t3) / (t1+t2+t3)
may make this clearer.

Answer 2

i think you shld draw the v-t graph first. calc the dist for each sectn i.e. d area of the triangles and the rectangle.
frm this dist, calc the velocity for each sectn and then find the ave.
at least that's what i think it is( ull hv to check it out though)