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The delta Hvapor of water is 40.7 kJ/mol.
I understand how to work the problem but I do not know where the book comes up with 9.81689 when you go to multiply vapor pressure one to get the pressure of the second one. Please help...confused!!!

2007-09-17 08:58:29 · 2 answers · asked by 00000000 1 in Science & Mathematics Chemistry

2 answers

at 34°C, the vapor pressure of water is 5.3229 kPa
at 35°C, VP = 5.6267 kPa

at 85°C VP = 57.815 kPa: at 86°C, VP = 60.119 kPa

Interpolating these values, the vapor pressure at 34.1°C ~ 5.3533 kPa = 40.153 torr

At 85.5°C, VP = 58.967 kPa = 442.29 torr

See if you can get your answer to match that . . .

2007-09-17 09:28:54 · answer #1 · answered by Dave_Stark 7 · 0 2

it has to be an error by the book

2007-09-17 09:19:20 · answer #2 · answered by Jonny C 2 · 0 1

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