2a (a - 5 ) - 2a (3a - 5) + a ² + 3a
Thx
2007-09-17 08:03:13 · 6 answers · asked by Dante Alighieri 3 in Science & Mathematics ➔ Mathematics
i'd like to have details if it is possible. THX
2007-09-17 08:14:35 · update #1
2a (a - 5 ) - 2a (3a - 5) + a ² + 3a
2a² - 10a - 6a² + 10a + a ² + 3a
-3a² + 3a
2007-09-17 08:09:50 · answer #1 · answered by Marvin 4 · 0⤊ 0⤋
2a (a - 5 ) - 2a (3a - 5) + a ² + 3a
Distribute, getting:
2a^2-10a -6a^2 +10a +a^2 +3a
Collect like terms, getting
-3a^2 +3a
Factor, getting:
3a(1-a)
2007-09-17 08:23:32 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
Multiply through the ( )'s first:
2a*(a - 5) = 2a^2 - 10a
and
-2a*(3a-5) = -6a^2+10a
Now, rewrite:
2a^2-10a-6a^2+10a+a^2+3a
Now combine like terms:
-3a^2+3a
Now factor:
-3a(a - 1)
2007-09-17 08:10:24 · answer #3 · answered by miggitymaggz 5 · 0⤊ 0⤋
2a (a - 5) - 2a (3a - 5) + a ² + 3a =
2a (a - 5 -3a + 5) + a ² + 3a =
- 4a ²+ a ² + 3a =
- 3a ² + 3a =
3a (1 – a)
2007-09-17 08:28:29 · answer #4 · answered by Anonymous · 0⤊ 0⤋
expand
2a (a - 5 ) - 2a (3a - 5) + a ² + 3a = 2a*a - 2a*5 -2a*3a + 2a*5 = 2a² -10a -6a² +10a = -4a²
2007-09-17 08:07:54 · answer #5 · answered by antone_fo 4 · 0⤊ 0⤋
2a^2 - 10a - 6a^2 + 10a + a^2 + 3a = -3a^2 + 3a = 3a(1 - a)
2007-09-17 08:10:16 · answer #6 · answered by John V 6 · 0⤊ 0⤋